CKM Mixing Unitarity Triangle

What you are seeing: the CKM unitarity condition $V_{ud}V^*_{ub} + V_{cd}V^*_{cb} + V_{td}V^*_{tb} = 0$ drawn as three complex side-vectors added tip-to-tail, closing the triangle with vertices $(0,0)$ , $(1,0)$ , $(\bar\rho, \bar\eta)$ and angles $\alpha, \beta, \gamma$ . The enclosed area is the Jarlskog invariant, so the CP-asymmetry panel shows the $B^0$ vs $\bar B^0$ golden-mode rates ( $\propto \sin 2\beta$ ): a flat triangle gives equal rates (no CP violation), a fat one a large asymmetry. Drag $\bar\rho, \bar\eta$ to move the apex.

Figure 1. CKM matrix and unitarity triangle.

ρ̄0.157

η̄0.355

WHAT TO TRY

Drag the apex (rho-bar, eta-bar): the three CKM side-vectors stay tip-to-tail and the triangle keeps closing, because unitarity forces the sum to zero. The angles alpha, beta, gamma always add to 180 degrees.
Flatten the triangle toward the real axis (eta-bar to 0): the area collapses and so does the Jarlskog invariant, the single measure of CP violation. A degenerate triangle means no CP violation.
Compare the apex against the CP-asymmetry bars: a non-zero height eta-bar is what makes the B0 and B0-bar decay rates differ, the matter-antimatter asymmetry the experiments measure.