Blackbody Radiation: Planck vs Rayleigh-Jeans
At the end of the nineteenth century classical physics made a catastrophic prediction. Treating the radiation in a hot cavity as a sum of wave modes, each carrying the same thermal energy $k_B T$, the Rayleigh-Jeans law says the spectral radiance is $2c k_B T/\lambda^4$, which grows without bound as the wavelength shrinks: a hot oven should blaze with infinite ultraviolet light. It does not, and the disagreement was called the ultraviolet catastrophe. Planck's fix in 1900 was to assume the oscillators could only exchange energy in discrete quanta $h\nu$, which gives $B_\lambda = (2hc^2/\lambda^5)/(e^{hc/\lambda k_B T} - 1)$. At long wavelengths the quantum is tiny and Planck reduces exactly to Rayleigh-Jeans, but at short wavelengths the exponential starves the high-frequency modes and the curve turns over and falls to zero, matching every measurement. Slide the temperature and watch the Planck peak shift to shorter wavelengths (Wien's law $\lambda_\text{max}T = $ constant) and the whole curve swell, with the total radiated power climbing as $T^4$ (Stefan-Boltzmann). This single plot launched quantum physics.
WHAT TO TRY
- Raise the temperature: the Planck peak slides to shorter wavelengths (a cool star is red, a hot one blue) and the whole curve grows, while the Rayleigh-Jeans curve always shoots off the top.
- Notice that the two curves agree at long wavelengths and only part ways toward the short, ultraviolet end, where the classical law diverges and Planck's turns over.
- Read Wien's law in the green marker: $\lambda_\text{max}T$ stays constant (about 2.9 mm K) as you change T.
- Watch the bottom plot: the total radiated power follows a straight line of slope four on log-log axes, so doubling T multiplies the power by sixteen (Stefan-Boltzmann).